
Quadratic RELATIONS

Finding Zeros
Finding the zeros or x-intercepts, you find them from the form of vertex form.
To find the y intercepts, you sub in y=0, and to find the x intercepts you sub in y=0
For Example 1: y= 2(x-6)-40
Find y-intercept, set x=0 Find x-intercept, y=0
y= 2(0-6)^2-40 0=2(x-5)^2-40 Step 1: Set y-intercept
y= 2(-6)^2-40 40=2(x-5)^2 Step 2: Bring the -40 over the equal sign
y= 2(36)-40 40=2(x-5)^2 Step 3: Divide everything by 2 to isolate for x
y= 72-40 2 2 Step 4: Cancel out the 2
y= 32 20=(x-5)^2 Step 5: The opposite of squaring is square rooting
x-5= (+)(-) √20
Therefore, the y-intercept is (0,32)
Therfore, the two possible roots (9.5,0) and (0.5,0)
x= -√20+5
x= -4.5+5
x= 0.5
x= +√20+5
x= 4.5+5
x= 9.5
Now lets try:
1) y= 2(x+5)^2-50 2) y= 4(x+10)-5
Answers:
